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Question

${cos}^{2} 42^{\circ} - {sin}^{2} 48^{\circ}$

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Solution

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${cos}^{2} 42^{\circ} - {sin}^{2} 48^{\circ}$
= ${cos}^{2} (90 - 48)^{\circ} - {sin}^{2} 48^{\circ}$
= ${sin}^{2} 48^{\circ} - {sin}^{2} 48^{\circ}$
= $0$

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