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(cosA+cosBsinA−sinB)n+(sinA+sinBcosA−cosB)n=⎧⎩⎨2cotn(A−B2), if n is even0, if n is odd(cos⁡A+cos⁡Bsin⁡A−sin⁡B)n+(sin⁡A+sin⁡Bcos⁡A−cos⁡B)n={2cotn⁡(A−B2), if n is even0, if n is odd

A
True
B
False
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Correct option is A. True

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