Critical angle of glass is theta-1- and that of water is theta-2- The critical angle water and glass surface would be -mu-g- - 3-2- mu-w- - 4-3-Greater than theta-2-Between theta-1- and theta-2-Less than theta-2-Less than theta-1-

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Toppr Admin · Accepted Answer

Sin-x3B8-1-1-x3BC-g and sin-x3B8-2-1-x3BC-wSince -x3BC-g-gt-x3BC-w-x3B8-1-lt-x3B8-2Critical angle -x3B8- between glass and water will be given bysin-x3B8-x3BC-w-x3BC-gor -x3B8-gt-x3B8-2Note- Critical angle increases as the relative refractive index is decreased-

Critical angle of glass is $θ_{1}$ and that of water is $θ_{2}$ . The critical angle for water and glass surface would be $(μ_{g} = 3 / 2, μ_{w} = 4 / 3)$ .
Greater than $θ_{2}$
Between $θ_{1}$ and $θ_{2}$
Less than $θ_{2}$
Less than $θ_{1}$

$sin θ_{1} = \frac{1}{μ_{g}}$ and $sin θ_{2} = \frac{1}{μ_{w}}$
Since $μ_{g} > μ_{w}, θ_{1} < θ_{2}$
Critical angle $θ$ between glass and water will be given by
$sin θ = \frac{μ_{w}}{μ_{g}}$
or $θ > θ_{2}$
Note: Critical angle increases as the relative refractive index is decreased.

Critical angle of glass is θ1 and that of water is θ2. The critical angle for water and glass surface would be (μg=3/2,μw=4/3).Greater than θ2Between θ1 and θ2Less than θ2Less than θ1

sinθ1=1μg and sinθ2=1μwSince μg>μw,θ1<θ2Critical angle θ between glass and water will be given bysinθ=μwμgor θ>θ2Note: Critical angle increases as the relative refractive index is decreased.

Critical angle of glass is $θ_{1}$ and that of water is $θ_{2}$ . The critical angle for water and glass surface would be $(μ_{g} = 3 / 2, μ_{w} = 4 / 3)$ .
Greater than $θ_{2}$
Between $θ_{1}$ and $θ_{2}$
Less than $θ_{2}$
Less than $θ_{1}$

$sin θ_{1} = \frac{1}{μ_{g}}$ and $sin θ_{2} = \frac{1}{μ_{w}}$
Since $μ_{g} > μ_{w}, θ_{1} < θ_{2}$
Critical angle $θ$ between glass and water will be given by
$sin θ = \frac{μ_{w}}{μ_{g}}$
or $θ > θ_{2}$
Note: Critical angle increases as the relative refractive index is decreased.