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Question

Currents I1 and I2 flow in the wires shown in figure. The field is zero at distance x to the right of O. Then
166819_46b8b775b1094f8b8a0dd3ac654544b6.PNG
  1. x=(I1I2)a
  2. x=(I2I1)a
  3. x=(I1I2I1+I2)a
  4. x=(I1+I2I1I2)a

A
x=(I1I2I1+I2)a
B
x=(I1+I2I1I2)a
C
x=(I1I2)a
D
x=(I2I1)a
Solution
Verified by Toppr

Magnetic field with both wire will be equal and opposite in diretion,
μ0I14π(a+x)=μ0I24π(ax)

axa+x=I2I1

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