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Question

# Currents I1 and I2 flow in the wires shown in figure. The field is zero at distance x to the right of O. Thenx=(I1I2)ax=(I2I1)ax=(I1−I2I1+I2)ax=(I1+I2I1−I2)a

A
x=(I1I2I1+I2)a
B
x=(I1+I2I1I2)a
C
x=(I1I2)a
D
x=(I2I1)a
Solution
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#### Magnetic field with both wire will be equal and opposite in diretion,μ0I14π(a+x)=μ0I24π(a−x)a−xa+x=I2I1

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