Define capacitance of a capacitor and its SI unit.

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Answer 1

The capacitance of any capacitor is its ability to store charge
$C = \frac{Q}{V}$
$C =$ capacitance
$Q =$ Charge
$V =$ Potential across capacitor.
The SI unit of capacitance is farad(F).

Answer 2

The capacitance of any capacitor is its ability to store charge

C = \frac{Q}{V}

C =

capacitance

Q =

Charge

V =

Potential across capacitor.
The SI unit of capacitance is farad(F).

Define capacitance of a capacitor and its SI unit.

Solution

The capacitance of any capacitor is its ability to store charge
$C = \frac{Q}{V}$
$C =$ capacitance
$Q =$ Charge
$V =$ Potential across capacitor.
The SI unit of capacitance is farad(F).

Patterns of problems

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Define capacitance of a capacitor and its SI unit.

The capacitance of any capacitor is its ability to store charge C=VQ​ C= capacitance Q= Charge V= Potential across capacitor. The SI unit of capacitance is farad(F).

Patterns of problems

Was this answer helpful?

Similar questions

A parallel plate capacitor with air between the plates has a capacitance of 8pF. the separation between the plates is now reduced by its half and the space between them is filled with a medium of dielectric constant 5. Calculate the value of capacitance of the capacitor in the second case.

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The gap between the plates of a parallel plate capacitor of area A and distance between platesd, is filled with a dielectric whose permittivity varies linearly from ∈1 at one plate to ∈2 at the other. The capacitance of capacitor is:

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A circuit consisting of a capacitor and a coil in series is connected to the mains. Varying the capacitance of the capacitor, the horse power generated in the coil was increased n=1.7 times. How much % was the value of cos∅ changed in the process?

More From Chapter

Electrostatic Potential and Capacitance

Shortcuts & Tips

Common misconceptions

Cheatsheets

Mindmap

Problem solving tips

Memorization tricks

Diagram set

Practice more questions

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The capacitance of any capacitor is its ability to store charge
$C = \frac{Q}{V}$
$C =$ capacitance
$Q =$ Charge
$V =$ Potential across capacitor.
The SI unit of capacitance is farad(F).

A parallel plate capacitor with air between the plates has a capacitance of $8 p F$ . the separation between the plates is now reduced by its half and the space between them is filled with a medium of dielectric constant $5$ . Calculate the value of capacitance of the capacitor in the second case.

The gap between the plates of a parallel plate capacitor of area $A$ and distance between plates $d$ , is filled with a dielectric whose permittivity varies linearly from $\in^{1}$ at one plate to $\in^{2}$ at the other. The capacitance of capacitor is:

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A circuit consisting of a capacitor and a coil in series is connected to the mains. Varying the capacitance of the capacitor, the horse power generated in the coil was increased n=1.7 times. How much $%$ was the value of $c o s \emptyset$ changed in the process?