Delta u-x is uncertainty in velocity of electron and Delta x-y is uncertainty in position- then-displaystyle Delta u-xcdot Delta x-y-frac-h-4pi-displaystyle Delta u-xcdot Delta x-y-frac-h-4pi m-displaystyle Delta u-xcdot Delta x-yge h-4pi mnone of these

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Toppr Admin · Accepted Answer

According to-xA0-Heisenberg principle-x394-x-x394-P-x2265-h-4-x3C0- when they both are measured on same axis-But when they are measured for different axis nothing can be said about their error or they can be measured 100- accurate-

$Δ u_{x}$ is uncertainty in velocity of electron and $Δ x_{y}$ is uncertainty in position, then:
$Δ u_{x} \cdot Δ x_{y} = \frac{h}{4 π}$
$Δ u_{x} \cdot Δ x_{y} = \frac{h}{4 π m}$
$Δ u_{x} \cdot Δ x_{y} \geq h / 4 π m$
none of these

According to Heisenberg principle,
$Δ x . Δ P \geq h / 4 π$ when they both are measured on same axis.
But when they are measured for different axis nothing can be said about their error or they can be measured 100% accurate.

Δux is uncertainty in velocity of electron and Δxy is uncertainty in position, then:Δux⋅Δxy=h4πΔux⋅Δxy=h4πmΔux⋅Δxy≥h/4πmnone of these

According to Heisenberg principle,Δx.ΔP≥h/4π when they both are measured on same axis.But when they are measured for different axis nothing can be said about their error or they can be measured 100% accurate.

$Δ u_{x}$ is uncertainty in velocity of electron and $Δ x_{y}$ is uncertainty in position, then:
$Δ u_{x} \cdot Δ x_{y} = \frac{h}{4 π}$
$Δ u_{x} \cdot Δ x_{y} = \frac{h}{4 π m}$
$Δ u_{x} \cdot Δ x_{y} \geq h / 4 π m$
none of these

According to Heisenberg principle,
$Δ x . Δ P \geq h / 4 π$ when they both are measured on same axis.
But when they are measured for different axis nothing can be said about their error or they can be measured 100% accurate.