Density of a gas is found to be 5-46 dmdisplaystyle -3- 27 displaystyle -circ-C 2 bar pressure- What will be its density STP-

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Toppr Admin · Accepted Answer

The expression for density is d-PMRT-For a given gas- R and M are constant-d-x221D-P-Td-x2032-dP-x2032-TPT-x2032-5-46-xD7-1-xD7-3002-xD7-273-3-0-xA0-g-xA0-dm-x2212-3

Density of a gas is found to be 5.46 dm $^{3}$ at 27 $^{\circ} C$ at 2 bar pressure. What will be its density at STP?

The expression for density is $d = \frac{P M}{R T}$ .

For a given gas, R and M are constant.

$d \propto P / T$

$d^{'} = \frac{d P^{'} T}{P T^{'}} = \frac{5.46 \times 1 \times 300}{2 \times 273} = 3.0 g d m^{- 3}$

Density of a gas is found to be 5.46 dm3 at 27 ∘C at 2 bar pressure. What will be its density at STP?

The expression for density is d=PMRT.For a given gas, R and M are constant.d∝P/Td′=dP′TPT′=5.46×1×3002×273=3.0 g dm−3

Density of a gas is found to be 5.46 dm $^{3}$ at 27 $^{\circ} C$ at 2 bar pressure. What will be its density at STP?

The expression for density is $d = \frac{P M}{R T}$ .

For a given gas, R and M are constant.

$d \propto P / T$

$d^{'} = \frac{d P^{'} T}{P T^{'}} = \frac{5.46 \times 1 \times 300}{2 \times 273} = 3.0 g d m^{- 3}$