Derive an expression for the magnetic dipole moment of a revolving electron.

Name: Derive an expression for the magnetic dipole moment of a revolving electron.
Uploaded: 2020-01-06
Description: Click here👆to get an answer to your question ✍️ Derive an expression for the magnetic dipole moment of a revolving electron.

Question

Verified by Toppr

Answer 1

The current in a loop due to a revolving electron $= \frac{q}{T}$ $= \frac{q}{2 π r / v}$ $= \frac{q v}{2 π r}$

Hence, magnetic moment due to the revolving charge $= I A$ $= \frac{q v}{2 π r} π r^{2}$ $= \frac{q v r}{2}$

Answer 2

The current in a loop due to a revolving electron

= \frac{q}{T}

= \frac{q}{2 π r / v}

= \frac{q v}{2 π r}

Hence, magnetic moment due to the revolving charge

= I A

= \frac{q v}{2 π r} π r^{2}

= \frac{q v r}{2}

Derive an expression for the magnetic dipole moment of a revolving electron.

The current in a loop due to a revolving electron $= \frac{q}{T}$ $= \frac{q}{2 π r / v}$ $= \frac{q v}{2 π r}$

Hence, magnetic moment due to the revolving charge $= I A$ $= \frac{q v}{2 π r} π r^{2}$ $= \frac{q v r}{2}$

Write the expression for the equivalent magnetic moment of a planer current loop of area $A$ . having $N$ turns and carrying a current $i$ . Use the expression to find the magnetic dipole moment of a revolving electron.

Deduce the expression for the magnetic dipole moment of an electron orbiting around central nucleus .

Deduce an expression for magnetic dipole moment of an electron revolving around a nucleus in a circular orbit. Indicate the direction of magnetic dipole moment? Use the expression to derive the relation between the magnetic moment of an electron moving in a circle and its related angular momentum?

If an electron is revolving in a circular orbit of radius $0.5 A^{o}$ with a velocity of $2.2 \times 1 0^{6} m / s$ . The magnetic dipole moment of the revolving electron is (Charge on electron $e = 1.6 \times 1 0^{- 19}$ )

If an electron is revolving in a circular orbit of radius $0.5 A^{\circ}$ with a velocity of $2.2 \times 1 0^{6}$ m/s. The magnetic dipole moment of the revolving electron is

Revise with Concepts

Dipole in Uniform Magnetic Field

Solve Question on Magnetic Dipoles

Derive an expression for the magnetic dipole moment of a revolving electron.

The current in a loop due to a revolving electron =Tq​ =2πr/vq​ =2πrqv​ Hence, magnetic moment due to the revolving charge =IA =2πrqv​πr2 =2qvr​

Write the expression for the equivalent magnetic moment of a planer current loop of area A. having N turns and carrying a current i. Use the expression to find the magnetic dipole moment of a revolving electron.

Deduce the expression for the magnetic dipole moment of an electron orbiting around central nucleus .

Deduce an expression for magnetic dipole moment of an electron revolving around a nucleus in a circular orbit. Indicate the direction of magnetic dipole moment? Use the expression to derive the relation between the magnetic moment of an electron moving in a circle and its related angular momentum?

If an electron is revolving in a circular orbit of radius 0.5 Ao with a velocity of 2.2×106 m/s. The magnetic dipole moment of the revolving electron is (Charge on electron e=1.6×10−19)

If an electron is revolving in a circular orbit of radius 0.5A∘ with a velocity of 2.2×106 m/s. The magnetic dipole moment of the revolving electron is

Revise with Concepts

Dipole in Uniform Magnetic Field

Solve Question on Magnetic Dipoles

The current in a loop due to a revolving electron $= \frac{q}{T}$ $= \frac{q}{2 π r / v}$ $= \frac{q v}{2 π r}$

Hence, magnetic moment due to the revolving charge $= I A$ $= \frac{q v}{2 π r} π r^{2}$ $= \frac{q v r}{2}$

Write the expression for the equivalent magnetic moment of a planer current loop of area $A$ . having $N$ turns and carrying a current $i$ . Use the expression to find the magnetic dipole moment of a revolving electron.

If an electron is revolving in a circular orbit of radius $0.5 A^{o}$ with a velocity of $2.2 \times 1 0^{6} m / s$ . The magnetic dipole moment of the revolving electron is (Charge on electron $e = 1.6 \times 1 0^{- 19}$ )

If an electron is revolving in a circular orbit of radius $0.5 A^{\circ}$ with a velocity of $2.2 \times 1 0^{6}$ m/s. The magnetic dipole moment of the revolving electron is