0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# Derive an expression for the magnetic dipole moment of a revolving electron.

Solution
Verified by Toppr

#### The current of an electron revolving around a heavy nucleus is given as:$I=\dfrac{e}{T}=\dfrac{e}{2\pi r/v}=\dfrac{ev}{2\pi r}$The magnetic moment associated to the current of an electron revolving is given as:$\mu_l=IA=\dfrac{ev}{2\pi r}(\pi r^2)=\dfrac{evr}{2}$.Substituting the angular momentum of the revolving electron we get,$l = mvR$$vR=\frac{l}{m}Therefore, \mu_l=\frac{el}{2m}$$\frac{\mu_l}{l}=\frac{e}{2m}$.The above equation is known as Gyromagnetic ratio.

56
Similar Questions
Q1
Derive an expression for the magnetic dipole moment of a revolving electron.
View Solution
Q2
Deduce the expression for the magnetic dipole moment of an electron orbiting around central nucleus .
View Solution
Q3
Write the expression for the equivalent magnetic moment of a planer current loop of area A. having N turns and carrying a current i. Use the expression to find the magnetic dipole moment of a revolving electron.
View Solution
Q4
If an electron is revolving in a circular orbit of radius 0.5A with a velocity of 2.2×106 m/s. The magnetic dipole moment of the revolving electron is
View Solution
Q5
Show that the orbital magnetic dipole moment of revolving electron is evr2
View Solution