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Question

Derive the following expression for the refraction at concave spherical surface: μv1u=μ1R.

Solution
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Let MPN be concabe spherical surface of a medium of refractive index μ. P is the pole o is the centre of curvature PC is the principle axis. Let O be a point object or it's principle axis kept in a rarer medium first incident ray travelling through C is normal to the spherical surface therefor it will not deviate and goes along PX another mident ray OA will refract at Point A and it bends towards the normal. AB and PX are proceeded behind then at I, a virtual image will be form.
Let α,β,γ are the ray angle normal with the principle axis respectively.
then by snell's law
μ=sinisinr ........(1)
but here i and r are the small then we put.
sini=i sinr=r in equation (1)
μ=ir
i=μn ...........(2)
now by using exterior angle theorem in ΔAOC
γ=1+a
i=γα .........(3)
now in ΔIAC by using exterior angle theorem
γ=b+r
rho=γβ ..........(4)
putting value of i and r in equation (2)
(γα)=μ(γβ) ...........(5)
now angle=arcradius
α=PAOP
β=PAIP
now γ=PACP
using value of α,β,γ in equation (5)
PAPCPAPO=μ(PAPCPAPI)
PA(1PC1PO)=m.PA(1PC1PO)
1PC1PO=μ(1PC1PI) .........(6)
now by using sign convention
PC=R PI=V
PO=u
using these value in equation (6)
(1R)(1u)=μ(1R+1V)
1R+1u=μ(1R+1v)
1R+1u=μR+μv
1R+μR=μv1u
μ1R=μv1u
This is the required expression for the refraction formula for the concave spherical surface.
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Derive the following expression for the refraction at concave spherical surface: μv1u=μ1R.
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