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Describe the manufacture of $H_{2} S O_{4}$ by contact process?

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The steps involved in the manufacture of sulphuric acid by contact process are as shown:

(1) Sulphur (or iron pyrites) are burnt in air to form sulphur dioxide.
$S + O_{2} \to S O_{2} 4 F e S_{2} + 11 O_{2} \to 2 F e_{2} O_{3} + 8 S O_{2}$
(2) Catalytic oxidation of sulphur dioxide to sulphur trioxide.
$2 S O_{2} + O_{2} V_{2} O_{5} - -- \to 2 S O_{3} Δ_{r} H^{o} = - 196.6$ kJ
The reaction is reversible and exothermic.
(3) Sulphur trioxide is dissolved in 98% sulphuric acid to form oleum (fuming sulphuric acid).
$S O_{3} + H_{2} S O_{4} \to H_{2} S_{2} O_{7}$
(4) Oleum is diluted with water to form sulphuric acid of desired concentration.
$H_{2} S_{2} O_{7} + H_{2} O \to 2 H_{2} S O_{4}$
and
Manufacture of $H_{2} S O_{4}$ by contact process involves three steps:
1. Burning of sulphur in air to generate $S O_{2}$ .
2. Conversion of $S O_{2}$ to $S O_{3}$ by oxidation with air in the presence of $V_{2} O_{5}$ as catalyst.
3. Absorption of $S O_{3}$ in $H_{2} S O_{4}$ to obtain oleum $H_{2} S_{2} O_{7}$ . A flow diagram for the manufacture of $H_{2} S O_{4}$ is given below:

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Q1

Describe the manufacture of

H_{2} S O_{4}

by contact process?

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Q2

In the manufacture of

H_{2} S O_{4}

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Describe the manufucature of $H_{2} S O_{4}$ by contact process,

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Manufacture of sulphuric acid by contact process involves dissolution of

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