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Question

Determine n if
i) 2nC3:nC3=12:1
ii) 2nC3:nC3=11:1

Solution
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i) 2nC3:nC3=12:1
2nC3=12×nC3
2n(2n1)(2n2)3!
=12×n(n1)(n2)3!
4(2n1)=12(n2)
2n1=3(n2)
2n1=3n6
n=61=5

ii) 2nC3:nC3=11:1
2nC3=11×nC3
2n(2n1)(2n2)3!
=11×n(n1)(n2)3!
4(2n1)=11(n2)
8n4=11n22
11n8n=224
3n=18
n=6

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