A fully charged capacitor no current draws from cell. So, no current flow in the capacitor branch and corresponding circuit is shown in figure. Total resistance of the circuit is Rt=2.8+2∣∣3=2.8+2+32×3=2.8+1.2=4Ω Current in the circuit is I=46=1.5A If I1 and I2 are the current through 2Ω and 3Ω respectively, then I=I1+I2...(1) As 2Ω and 3Ω are in parallel so V2Ω=V3Ω or 2I1=3I2⇒I2=(2/3)I1 now, (1) becomes, 1.5=I1+(2/3)I1=35I1 or I1=51.5×3=0.9A