Determine the current through zener diode for the circuit shown in figure is: (Given: zener diode break down voltage $V_z=5.6V$)

For zener brak down potential difference across $800\Omega$  resistor will be $5.6V$4
$V_z=5.6V$
$i_2=\frac{V_z}{800}=\frac{5.6}{800}=7mA$
$\Delta V$ across $200\Omega =9-5.6=3.4V$
$i_1=\frac{3.4}{200}=17mA$
$i_1=1_2+i_z$
$i_z=17mA-7mA=10mA$