Determine the greatest 3-digit number exactly divisible by 8- 10 and 12-

Question

Toppr Admin · Accepted Answer

LCM of -8- 10- and -12-LCM-2-times 2-times 2-times 3-times 5-120-We have to find the greatest -3-digit multiple of -120-It can be seen that -120-times 8-960- and -120-times 9-1080-Hence- the greatest -3-digit number exactly divisible by -8- 10- and -12- is -960-

Determine the greatest $$3$$-digit number exactly divisible by $$8$$, $$10$$ and $$12$$.

LCM of $$8, 10$$ and $$12$$
LCM$$=2\times 2\times 2\times 3\times 5=120$$
We have to find the greatest $$3$$-digit multiple of $$120$$.
It can be seen that $$120\times 8=960$$ and $$120\times 9=1080$$.
Hence, the greatest $$3$$-digit number exactly divisible by $$8, 10$$ and $$12$$ is $$960$$.

Determine the greatest $$3$$-digit number exactly divisible by $$8$$, $$10$$ and $$12$$.

LCM of $$8, 10$$ and $$12$$LCM$$=2\times 2\times 2\times 3\times 5=120$$We have to find the greatest $$3$$-digit multiple of $$120$$.It can be seen that $$120\times 8=960$$ and $$120\times 9=1080$$.Hence, the greatest $$3$$-digit number exactly divisible by $$8, 10$$ and $$12$$ is $$960$$.

LCM of $$8, 10$$ and $$12$$
LCM$$=2\times 2\times 2\times 3\times 5=120$$
We have to find the greatest $$3$$-digit multiple of $$120$$.
It can be seen that $$120\times 8=960$$ and $$120\times 9=1080$$.
Hence, the greatest $$3$$-digit number exactly divisible by $$8, 10$$ and $$12$$ is $$960$$.