Determine the potential difference across the plates of the capacitor $^{'} C_{1}^{'}$ of the network shown in the figure. [Assume $E_{2} > E_{1}$ ]

Question

Determine the potential difference across the plates of the capacitor -C-1- of the network shown in the figure- -Assume E-2 - E-1-

Toppr Admin · Accepted Answer

B-apos-As E2-gt-E1-xA0-x2234- the direction is clockwise-xA0-using kirchoff rule-xA0-qC2-x2212-E1-qC1-E2-0as V1-qC1-xA0-and-xA0-V2-qC2-x2234-V1-E1-x2212-E2-x2212-qC2-xA0- V2-E1-x2212-E2-x2212-qC1-xA0-xA0-apos-

Determine the potential difference across the plates of the capacitor ′C′1 of the network shown in the figure. [Assume E2>E1]

b'As E2>E1 ∴ the direction is clockwise using kirchoff rule, qC2−E1+qC1+E2=0as V1=qC1 and V2=qC2∴V1=E1−E2−qC2 V2=E1−E2−qC1 '

Determine the potential difference across the plates of the capacitor $^{'} C_{1}^{'}$ of the network shown in the figure. [Assume $∴ V_{1} = E_{1} - E_{2} - \frac{q}{C_{2}}$ ]

b'As $E_{2} > E_{1}$
$∴$ the direction is clockwise
using kirchoff rule,
$\frac{q}{C_{2}} - E_{1} + \frac{q}{C_{1}} + E_{2} = 0$
as $V_{1} = \frac{q}{C_{1}} a n d V_{2} = \frac{q}{C_{2}}$
$∴ V_{1} = E_{1} - E_{2} - \frac{q}{C_{2}}$
$V_{2} = E_{1} - E_{2} - \frac{q}{C_{1}}$
'