0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass $$m$$ is connected to a spring of spring constant $$k$$ as shown in Fig $$4.147$$. The block is found at its equilibrium position at $$t=1\ s$$ and it has a velocity of $$+0.25\ m/s$$ at $$t=2\ s$$. The time period oscillation is $$6\ s$$.
Based on the given information answer the following question:
Determine the velocity of particle at $$t=5\ s$$

A
$$0.5\ m/s$$
B
$$-0.4\ m/s$$
C
$$none\ of\ these$$
D
$$-0.25\ m/s$$
Solution
Verified by Toppr

Correct option is A. $$-0.4\ m/s$$

Was this answer helpful?
0
Similar Questions
Q1
A block of mass $$m$$ is connected to a spring of spring constant $$k$$ as shown in Fig $$4.147$$. The block is found at its equilibrium position at $$t=1\ s$$ and it has a velocity of $$+0.25\ m/s$$ at $$t=2\ s$$. The time period oscillation is $$6\ s$$.
Based on the given information answer the following question:
Determine the velocity of particle at $$t=5\ s$$

View Solution
Q2
A block of mass $$m$$ is connected to a spring of spring constant $$k$$ as shown in Fig $$4.147$$. The block is found at its equilibrium position at $$t=1\ s$$ and it has a velocity of $$+0.25\ m/s$$ at $$t=2\ s$$. The time period oscillation is $$6\ s$$.
Based on the given information answer the following questions:
The amplitude of oscillation is

View Solution
Q3
A particle performing S.H.M is found at its equilibrium at t=1 s and it is found to have a speed of 0.25 m/s at t=2 s.If the period of oscillation is 6 s.Calculate amplitude of oscillation
View Solution
Q4
A particle performing S.H.M is at its equilibrium when t=1 s and it is found to have a speed of 0.25 m/s at t=2 s. If the period of oscillation is 6 s. Calculate the amplitude of oscillation.
View Solution
Q5
A block of mass $$m$$ is connected to a spring of spring constant $$k$$ and is at rest in equilibrium as shown in figure (a). Now, the block is displaced by $$h$$ below its equilibrium position and imparted a speed $$v_{0}$$ towards down as shown in figure (b). As a result of the jerk, block executes simple harmonic motion about its equilibrium position.
Based on above information answer the following question:
The amplitude of oscillation is:

View Solution