Let p(x)=6x2+13x+6 By the factor theorem, 3x+2 is a factor of p(x), if p(−23)=0 Find the value of p(−23) p(x)=6x2+13x+6 p(−23)=6(−23)2+13(−23)+6 0=6×49−263+6 0=83−263+6 0=−183+6 0=−6+6 0=0 Therefore, 3x+2 is a factor of p(x).
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