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Question

Determine whether the following is even or odd
f(x)=sgn(x)+x2
  1. neither even nor odd
  2. even
  3. odd and periodic
  4. odd

A
neither even nor odd
B
even
C
odd
D
odd and periodic
Solution
Verified by Toppr

x2 is an even function, however sgn(x) is an odd function.
Hence the above function is neither odd nor even.

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