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Standard VI
Maths
Operations on Fractions
Question
$$ \dfrac{17}{9} + \dfrac{41}{9} $$=_____.
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Solution
Verified by Toppr
$$ \dfrac{17}{9} + \dfrac{41}{9} = \dfrac {58}{9} $$
Explanation
$$ \Rightarrow \dfrac {17}{8} + \dfrac {41}{9} = \dfrac { 17 + 41}{8} = \dfrac { 58}{9} $$
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