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Question

$\frac{a^{2} - b^{2}}{a - b} i s e q u a l t o$
$(a - b)^{2}$
$a + b$
$a - b$
$a^{2} + b^{2}$

A

a + b

B

a - b

C

(a - b)^{2}

D

a^{2} + b^{2}

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Solution

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$\frac{a^{2} - b^{2}}{a - b}$ (we know that $a^{2} - b^{2} = (a + b) (a - b))$

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Q1

\frac{a^{2} - b^{2}}{a - b} i s e q u a l t o

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Q2

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}}

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Q3

If θ =

\frac{a}{b}

, then

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\frac{(a^{2} + b^{2})}{(a^{2} - b^{2})}

(b)

\frac{(a^{2} - b^{2})}{(a^{2} + b^{2})}

(c)

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(d)

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Q4

Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

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Q5

Simplify:

\frac{a^{2} - {(b - c)}^{2}}{{(a + c)}^{2} - b^{2}} + \frac{b^{2} - {(a - c)}^{2}}{{(a + b)}^{2} - c^{2}} + \frac{c^{2} - {(a - b)}^{2}}{{(b + c)}^{2} - a^{2}}

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