Differentiate the following from first principle.
$$\dfrac{\sin x}{x}$$.
A
$$\dfrac{-x\cos x+\sin x}{x^2}$$.
B
$$\dfrac{x\cos x-\sin x}{x^2}$$.
C
$$\dfrac{-x\sin x+\cos x}{x^2}$$.
D
$$\dfrac{x\sin x-\cos x}{x^2}$$.
Correct option is B. $$\dfrac{x\cos x-\sin x}{x^2}$$.
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