Dimension of work done isleft- L - - 2 - M - - 1 - T - - -2- right-left- L - - 2 - M - - 2 - T - - 2 - right-left- L - - 2 - M - - 0 - T - - 0 - right-left- L - - 2 - M - - 2 - T - - -3 - right-

Question

Toppr Admin · Accepted Answer

We know that-xA0-Work done - Force -xD7- Displacement-xA0-W-MLT-x2212-2-xD7-L-ML2T-x2212-2-

Dimension of work done is
$[L^{2} M^{1} T^{- 2}]$
$[L^{2} M^{2} T^{2}]$
$[L^{2} M^{0} T^{0}]$
$[L^{2} M^{2} T^{- 3}]$

We know that
Work done = Force $\times$ Displacement
$W = M L T^{- 2} \times L = [M L^{2} T^{- 2}]$

Dimension of work done is[L2M1T−2][L2M2T2][L2M0T0][L2M2T−3]

We know that Work done = Force × Displacement W=MLT−2×L=[ML2T−2]

Dimension of work done is
$[L^{2} M^{1} T^{- 2}]$
$[L^{2} M^{2} T^{2}]$
$[L^{2} M^{0} T^{0}]$
$[L^{2} M^{2} T^{- 3}]$

We know that
Work done = Force $\times$ Displacement
$W = M L T^{- 2} \times L = [M L^{2} T^{- 2}]$