Dipole moment is shown by -trans-1- 2-dichlorobutenecis-1- 2-dichlorobutenetrans-2- 3-dichloro-2-butene1- 4-dichlorobenzene

Question

Toppr Admin · Accepted Answer

The dipole moment is shown by cis-x2212-1-2-x2212-dichlorobutene and trans-x2212-1-2-x2212-dichlorobutene-On the other hand- 1-4-x2212-dichlorobenzene and trans-x2212-2-3-x2212-dichloro-x2212-2-x2212-butene shows zero dipole moment as individual bond dipoles cancel each other due to symmetrical nature of the molecule-

Dipole moment is shown by :trans−1,2−dichlorobutenecis−1,2−dichlorobutenetrans−2,3−dichloro−2−butene1,4−dichlorobenzene

The dipole moment is shown by cis−1,2−dichlorobutene and trans−1,2−dichlorobutene.On the other hand, 1,4−dichlorobenzene and trans−2,3−dichloro−2−butene shows zero dipole moment as individual bond dipoles cancel each other due to symmetrical nature of the molecule.

Dipole moment is shown by :
$t r a n s - 1, 2 - d i c h l o r o b u t e n e$
$c i s$ $- 1, 2 -$ $d i c h l o r o b u t e n e$
$t r a n s$ $- 2, 3 -$ dichloro $- 2 -$ $b u t e n e$
$1, 4 -$ $d i c h l o r o b e n z e n e$