Displaystyle 4y-y-2-4-displaystyle left - y-2 right -left - y-2 right -displaystyle left - y-2 right -left - 2-y right -displaystyle left - y-2 right -left - y-2 right -displaystyle left - y-2 right -left - y-2 right -

Question

Toppr Admin · Accepted Answer

4y-x2212-y2-x2212-4-xA0-x2212-y2-x2212-4y-4-xA0-x2212-y2-x2212-2y-x2212-2y-22-x2212-y-y-x2212-2-x2212-2-y-x2212-2- -x2212-y-x2212-2-y-x2212-2-y-x2212-2-2-x2212-y-

$4 y - y^{2} - 4$ =_____
$(y - 2) (y - 2)$
$(y - 2) (2 - y)$
$(y - 2) (y + 2)$
$(y + 2) (y + 2)$

$4 y - y^{2} - 4$
= $- [y^{2} - 4 y + 4]$
= $- [y^{2} - 2 y - 2 y + 2^{2}]$
= $- [y (y - 2) - 2 (y - 2)]$
= $- (y - 2) (y - 2) = (y - 2) (2 - y)$

4y−y2−4=_____(y−2)(y−2)(y−2)(2−y)(y−2)(y+2)(y+2)(y+2)

4y−y2−4= −[y2−4y+4]= −[y2−2y−2y+22]=−[y(y−2)−2(y−2)]= −(y−2)(y−2)=(y−2)(2−y)

$4 y - y^{2} - 4$ =_____
$(y - 2) (y - 2)$
$(y - 2) (2 - y)$
$(y - 2) (y + 2)$
$(y + 2) (y + 2)$

$4 y - y^{2} - 4$
= $- [y^{2} - 4 y + 4]$
= $- [y^{2} - 2 y - 2 y + 2^{2}]$
= $- [y (y - 2) - 2 (y - 2)]$
= $- (y - 2) (y - 2) = (y - 2) (2 - y)$