$a_{n} = (- 1)^{n - 1} n^{3}; a_{9}$

Question

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Answer 1

We have, $a_{n} = (- 1)^{n - 1} n^{3}$
For, $a_{9}, n = 9$
$∴ a_{9} = (- 1)^{9 - 1} (9)^{3} = (9)^{3} = 729$

Answer 2

We have,

a_{n} = (- 1)^{n - 1} n^{3}

For,

a_{9}, n = 9

∴ a_{9} = (- 1)^{9 - 1} (9)^{3} = (9)^{3} = 729