ΔUo of combustion of methane is −XkJmole−1. The value of ΔHo is:
=ΔU0
<ΔU0
>ΔU0
=0
A
<ΔU0
B
=ΔU0
C
>ΔU0
D
=0
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Solution
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The correct option is B <ΔU0 ΔUo of combustion of methane is −XkJmole−1. The value of ΔHo is <ΔU0 For the combustion of methane, Δn is negative. Hence, ΔHo=ΔUo+ΔnRT<ΔUo
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