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Standard XII
Mathematics
Question
∫
1
0
3
x
+
1
−
4
x
−
1
12
x
d
x
=
9
4
l
o
g
4
e
9
4
l
o
g
4
e
−
1
6
l
o
g
3
e
l
o
g
4
3
None of these
A
9
4
l
o
g
4
e
B
None of these
C
9
4
l
o
g
4
e
−
1
6
l
o
g
3
e
D
l
o
g
4
3
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Solution
Verified by Toppr
∫
1
0
3
x
+
1
−
4
x
−
1
12
x
d
x
=
∫
1
0
(
3
4
x
−
1
4
.
1
3
x
)
d
x
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