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Standard XII
Mathematics
Integration Using Substitution
Question
∫
2
1
(
1
+
x
log
x
x
)
e
x
d
x
=
e
2
l
o
g
2
1
2
log2
e
2
2
log2
e
l
o
g
2
A
e
2
l
o
g
2
B
1
2
log2
C
e
2
2
log2
D
e
l
o
g
2
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Solution
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∫
2
1
(
1
+
x
log
x
x
)
e
x
d
x
∫
2
1
(
1
x
+
log
x
)
e
x
d
x
∫
e
x
[
f
(
x
)
+
f
′
(
x
)
]
d
x
=
e
x
f
(
x
)
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