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Question

$lim x \to 0 \frac{x tan 2 x - 2 x tan x}{(1 - cos 2 x)^{2}}$ =
$2$
$- 2$
$- \frac{1}{2}$
$\frac{1}{2}$

A

- \frac{1}{2}

B

- 2

C

\frac{1}{2}

D

2

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Solution

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$lim x \to 0 \frac{x tan 2 x - 2 x tan x}{(1 - cos 2 x)^{2}}$

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