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Standard XII
Maths
Question
tan
θ
+
cot
θ
=
sec
θ
c
o
s
e
c
θ
sin
θ
cos
θ
tan
θ
cot
θ
sin
θ
+
cos
θ
A
sec
θ
c
o
s
e
c
θ
B
sin
θ
+
cos
θ
C
tan
θ
cot
θ
D
sin
θ
cos
θ
Open in App
Solution
Verified by Toppr
Write
tan
θ
=
sin
θ
cos
θ
a
n
d
cot
θ
=
cos
θ
sin
θ
and simplify
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13
Similar Questions
Q1
Prove :
cos
2
θ
1
−
tan
θ
+
sin
3
θ
sin
θ
−
cos
θ
=
1
+
sin
θ
cos
θ
View Solution
Q2
(i)
cosecθ
+
cotθ
cosecθ
-
cotθ
=
(
cosecθ
+
cotθ
)
2
=
1
+
2
cot
2
+
2
cosecθ
cotθ
(ii)
secθ
+
tanθ
secθ
-
tanθ
=
(
secθ
+
tanθ
)
2
=
1
+
2
tan
2
θ
+
2
secθ
tanθ
View Solution
Q3
If
tan
θ
1
−
cos
θ
+
cot
θ
1
−
tan
θ
=
m
+
sec
θ
cosec
θ
.Find
m
View Solution
Q4
Prove the following.
(1) secθ (1 – sinθ) (secθ + tanθ) = 1
(2) (secθ + tanθ) (1 – sinθ) = cosθ
(3) sec
2
θ + cosec
2
θ = sec
2
θ × cosec
2
θ
(4) cot
2
θ – tan
2
θ = cosec
2
θ – sec
2
θ
(5) tan
4
θ + tan
2
θ = sec
4
θ – sec
2
θ
(6)
1
1
-
sin
θ
+
1
1
+
sin
θ
=
2
sec
2
θ
(7) sec
6
x
– tan
6
x
= 1 + 3sec
2
x
× tan
2
x
(8)
tan
θ
s
e
c
θ
+
1
=
s
e
c
θ
-
1
tan
θ
(9)
tan
3
θ
-
1
tan
θ
-
1
=
sec
2
θ
+
tan
θ
(10)
sin
θ
-
cos
θ
+
1
sin
θ
+
cos
θ
-
1
=
1
sin
θ
-
tan
θ
View Solution
Q5
Show that,
⎡
⎣
1
−
tan
θ
2
tan
θ
2
1
⎤
⎦
⎡
⎣
1
tan
θ
2
−
tan
θ
2
1
⎤
⎦
−
1
=
[
cos
θ
−
sin
θ
sin
θ
cos
θ
]
.
View Solution