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Question

Distinguish between the role of iodine and iodide ions in this experiment.

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Similar Questions
Q1
During the disproportionation of iodine to iodide and iodate ions, the ratio of iodate and iodide ions formed in alkaline medium is:
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Q2
During the disproportionation of Iodine to iodide and iodate ions, the ratio of iodate and iodide ions formed in alkaline medium is:

I2IO3+I
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Q3
A constant current flowed for 2 h through a potassium iodide solution, oxidizing the iodide ion to iodine. At the end of the experiment, the iodine was titrated with 72 ml of $$ 1.0 M\ Na_{2} S_{2} O_{3} $$ solution. What was the average rate of current flow, in ampere?
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Q4
Consider the disproportionation of Iodine to iodide and iodate ions. Using Oxidation method calculate the ratio of iodate and iodide ions formed in alkaline medium :

I2IO3+I
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Q5
Permanganate(VII) ion, MnO4 in basic solution oxidises iodide ion, I to produce molecular iodine (I2) and manganese (IV) oxide (MnO2). Write a balanced ionic equation to represent this redox reaction.
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