Divide 20 pens between Sheela and Sangeeta in the ratio of 3-2-

Question

Toppr Admin · Accepted Answer

Terms of -3-2- and -3- and -2-Sum of these terms-3-2-5-Sheela will get -3-5- of total pens and Sangeeta will get -2-5- of total pens-Number of pens with Sheela-dfrac-3-5-times 20-12-Number of pens with Sangeeta-dfrac-2-5-times 20-8-

Divide $$20$$ pens between Sheela and Sangeeta in the ratio of $$3:2$$.

Terms of $$3:2$$ and $$3$$ and $$2$$
Sum of these terms$$=3+2=5$$
Sheela will get $$3/5$$ of total pens and Sangeeta will get $$2/5$$ of total pens.
Number of pens with Sheela$$=\dfrac{3}{5}\times 20=12$$
Number of pens with Sangeeta$$=\dfrac{2}{5}\times 20=8$$.

Divide $$20$$ pens between Sheela and Sangeeta in the ratio of $$3:2$$.

Terms of $$3:2$$ and $$3$$ and $$2$$Sum of these terms$$=3+2=5$$Sheela will get $$3/5$$ of total pens and Sangeeta will get $$2/5$$ of total pens.Number of pens with Sheela$$=\dfrac{3}{5}\times 20=12$$Number of pens with Sangeeta$$=\dfrac{2}{5}\times 20=8$$.

Terms of $$3:2$$ and $$3$$ and $$2$$
Sum of these terms$$=3+2=5$$
Sheela will get $$3/5$$ of total pens and Sangeeta will get $$2/5$$ of total pens.
Number of pens with Sheela$$=\dfrac{3}{5}\times 20=12$$
Number of pens with Sangeeta$$=\dfrac{2}{5}\times 20=8$$.