Divide 39 into two parts such that their product is 324-

Question

Toppr Admin · Accepted Answer

Let first number be x-xA0-let the second number 39-x2212-x-x-39-x2212-x-324-x2212-x2-39x-x2212-324-0x2-x2212-39x-324-0x-x2212-27x-12x-324-0x-x-x2212-27-x2212-12-x-x2212-27-0x-12x-27-x2234-12 -amp- 29

Divide $39$ into two parts such that their product is $324$ .

Let first number be $x$
let the second number $39 - x$
$(x) (39 - x) = 324$
$- x^{2} + 39 x - 324 = 0$
$x^{2} - 39 x + 324 = 0$
$x - 27 x + 12 x + 324 = 0$
$x (x - 27) - 12 (x - 27) = 0$
$x = 12 x = 27$
$∴ 12$ & $29$

Divide 39 into two parts such that their product is 324.

Let first number be x let the second number 39−x(x)(39−x)=324−x2+39x−324=0x2−39x+324=0x−27x+12x+324=0x(x−27)−12(x−27)=0x=12x=27∴12 & 29

Divide $39$ into two parts such that their product is $324$ .

Let first number be $x$
let the second number $39 - x$
$(x) (39 - x) = 324$
$- x^{2} + 39 x - 324 = 0$
$x^{2} - 39 x + 324 = 0$
$x - 27 x + 12 x + 324 = 0$
$x (x - 27) - 12 (x - 27) = 0$
$x = 12 x = 27$
$∴ 12$ & $29$