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Question

Divide the sum of $$\dfrac{-1}{3}$$ and $$\dfrac{5}{6}$$ by the sum of the $$\dfrac{1}{-4}$$ and $$\dfrac{3}{8}$$.

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Solution
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Sum of $$\dfrac{-1}{3}$$ and $$\dfrac{5}{6}$$ gives $$\dfrac{-1}{3}+\dfrac{5}{6}=\dfrac{-2+5}{6}=\dfrac{3}{6}=\dfrac{1}{2}$$

Sum of $$\dfrac{1}{-4}$$ and $$\dfrac{3}{8}$$ gives $$\dfrac{1}{-4}+\dfrac{3}{8}=\dfrac{-2+3}{8}=\dfrac{1}{8}$$

Dividing the sum of $$\dfrac{-1}{3}$$ and $$\dfrac{5}{6}$$ by the sum of the $$\dfrac{1}{-4}$$ and $$\dfrac{3}{8}$$ gives $$\dfrac{\dfrac{1}{2}}{\dfrac{1}{8}}=\dfrac{8}{2}=4$$

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