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Question

Divide
12xy(9x216y2)÷4xy(3x+4y)

Solution
Verified by Toppr

9x216y2=(3x)2(4y)2=(3x4y)(3x+4y)

(12xy(9x216y2))÷(4xy(3x+4y))=12xy(9x216y2)4xy(3x+4y)=12xy(3x4y)(3x+4y)4xy(3x+4y)=3(3x4y)

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Divide
12xy(9x216y2)÷4xy(3x+4y)
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