Question

Double convex lenses are to be manufactured from a glass of refractive index 1.55, with both faces of same radius of curvature. What is the radius of curvature required if the focal length is to be 20 cm?

A
11 cm
B
22 cm
C
7 cm
D
6 cm
Solution
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Lens maker's formula,
1f=(μ1)(1R11R2)
Here, f = 20 cm, μ = 1.55, R1 = R, R2 = -R
120=(1.551)(1R1(R))or120=0.55×2R
R=1.1×20=22cm

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