Question

Draw a line segment of length $7.6$ cm and divide it in the ratio $5:8$. Measure the two parts.

Answer 1

$Dividealinesegmentof$$7.6cm,$$lengthintheratio$ $5:8$

$andmeasure$.
$m:n=5:8$
$m+n=5+8=13$
$AC:CB=5:8$
$bymeasurement$ $:AC=3cm,CB=4.6cm$.
$Stepsofconstruction$:
$1.Drawanyray$ $AB$, $suchthat$ $AB=7.6cm$
$2.Draw$$A$$X$$rayatpoint$ $A$ $makingacuteangle$.
$3$.$Locatethepoints$ $A_1,A_2,A_3,........A_{13}$ $from$ $A$.
$4$. $Join$ $B{A}_{13}$.$Draw$ $B{A}_{13}||A_{5}C$.
$Now$ , $AC:CB=5:8$
$Ifmeasured$ ,$AC=3cm,CB=4.6cm$.