Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4cm and 3cm. Then construct another triangle whose sides are 53 times the corresponding sides of the given triangle.
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Solution
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Construct △ABC, the given right angled triangle, as follows:
Step 1: Draw base BC of length 4cm.
Step 2: Draw a right angle at point B.
Step 3: Draw an arc of radius 3cm on the right angle drawn from B and label that point as A
Step 4: Join A−C.
△ABC is the given triangle.
To construct △EBD∼△ABC:
Step 1: Draw a ray BX at an acute angle to line BC on the opposite side of A.
Step 2: Mark 5 equidistant points B1,B2,B3,B4,B5 on ray BX.
Step 3: Join B3 and C.
Step 4: Draw B5D parallel to B3C and label the intersection on the extension of BC as D.
Step 5: Draw DE parallel to BA and label the intersection with the extension of BA as E
△EBD is the required triangle.
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