Draw the graph the linear equation given below-x - 3 - 0

Question

Toppr Admin · Accepted Answer

X-3-0-gt-x-x2212-3In the linear equation x-x2212-3- there is no term for y- This means- that y can take any value- Points lying on the line x-x2212-3 can be -x2212-3-2-x2212-3-0- or -x2212-3-x2212-1- Plotting these points on the graph paper and joining them- we get the graph for x-x2212-3-

Draw the graph for the linear equation given below: $x + 3 = 0$

$x + 3 = 0 => x = - 3$
In the linear equation $x = - 3$ , there is no term for $y$ . This means, that $y$ can take any value.
Points lying on the line $x = - 3$ can be $(- 3, 2), (- 3, 0)$ or $(- 3, - 1)$ . Plotting these points on the graph paper and joining them, we get the graph for $x = - 3$ .

Draw the graph for the linear equation given below:x+3=0

x+3=0=>x=−3In the linear equation x=−3, there is no term for y. This means, that y can take any value. Points lying on the line x=−3 can be (−3,2),(−3,0) or (−3,−1). Plotting these points on the graph paper and joining them, we get the graph for x=−3.

Draw the graph for the linear equation given below: $x + 3 = 0$

$x + 3 = 0 => x = - 3$
In the linear equation $x = - 3$ , there is no term for $y$ . This means, that $y$ can take any value.
Points lying on the line $x = - 3$ can be $(- 3, 2), (- 3, 0)$ or $(- 3, - 1)$ . Plotting these points on the graph paper and joining them, we get the graph for $x = - 3$ .