Draw the graph of the equation $$2x + 3y = 12$$. From the graph, find the coordinates of the point:
(i) whose y-coordinates is $$3$$.
(ii) whose x-coordinate is $$-3$$.
$$2 x+3 y=12\cdots(1)$$
To draw the graph ,we need at least two solutions of the equation
Put $$x=0$$ in $$(1)$$
$$2(0)+3 y=12$$
$$\implies 3 y=12$$
$$\implies y=4$$
So $$\left(0,4\right)$$ is a solution of the equation
Put $$y=0$$ in $$(1)$$
$$2 x+3(0)=12$$
$$\implies 2 x= 12$$
$$\implies x=6$$
So $$(6,0)$$ is a solution of the equation
With these two equations we can draw graph of $$2x+3y=12$$
from the graph
$$\text{(i)} $$ when $$y=3$$ then $$x=1.5$$
So, point is $$(1.5,3)$$
$$\text{(ii)} $$ when $$x=-3$$ then $$y=6$$
So, point is $$(-3,6)$$