Draw the square ABCD of area 9 square centimetres.
⇒ Area of square =9cm2⇒ Area of square =(Side)2
⇒ 9=(Side)2
∴ Side=3cm
We know in square all sides of square are equal and each angle is 90o.
⇒ Draw a line line segment AB=3cm
⇒ Take A and B as center and draw an angle of 90o.
⇒ Cut off AD=3cm and BC=3cm
⇒ Join CD
∴ ABCD is a required square.