Draw two tangents to a circle of radius $$3.5$$ cm from a point $$P$$ at a distance of $$6.2$$ cm from its centre.
Steps of Construction :
1. Draw a circle of radius $$3.5$$ cm from centre point$$O$$
2. Set a point $$P$$ which is located at distance $$6.2$$ cm from point $$O$$. Join $$OP$$.
3. Draw a perpendicular bisector of $$OP$$ which cuts $$OP$$ at point $$Q$$.
4. Now, considering $$Q$$ as a centre and equal radius $$(OQ=PQ)$$.Draw a circle.
5. Both circles intersect at points $$A$$ and $$B$$.
6. Join $$PA$$ nd $$PB$$.
Therefore, $$AP$$ and $$BP$$ are the required tangents.