During a certain time interval, the angular position of a swinging door is described by $$\theta =5.00+1.0t+2.00t^2$$, where $$\theta$$ is in radians and $$t$$ is in seconds. Determine the angular position, angular speed, angular acceleration of the door at $$t=0$$

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

The angular position of a point on a roatating wheel is given by $$ \theta =2.0+4.0t^{2}+2.0t^{3} $$ , where $$ \theta $$ is in radians and t is in seconds. At t=0, 'what are (a) the point's angulatr position and (b) its angular velocity (c) What is its angular velocity at t=4.0 s (d) Calculate its angular acceleration at t=2.0 s. (e) Is its angular acceleration constant

View Solution

The angular position of a rotating disc is given as

θ = 6 t^{2} + 5 t - 4

where

θ

is in radians,

t

is in seconds. What is the average angular velocity for the first time interval from

t = 0 (s)

t = 4 (s)

View Solution

The angular position of a point on the rim of a rotating wheel is given by

θ = 4 t - 3 t^{2} + t^{3}

, where

θ

is in radians and

t

is in seconds. What is the instantaneous angular acceleration at

t = 2 sec

View Solution

The angular position of a point on the rim of a rotating wheel is given by $$ \theta=4.0 t-3.0 t^{2}+t^{3} $$ , where $$ \theta $$ is in radians and t is in seconds. What are the angular velocities at (a) t= 2.0 s and (b) t=4.0 s (c) What is the average angular acceleration for the time interval that begins at t=2,0 s and ends at t=4.0 s What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval

View Solution

A wheel rotates with a constant angular acceleration

ω_{0} = - 0.75

rad/s at time t=0.Consider angular position at t=0 as

θ_{0} = 0

.Find out
(a)angular speed at t=5s
(b)it's angular position at time t=5s
(c)how much time will it take to reach an angular position of

θ = 10

radian?

View Solution