During decomposition of H-2-O-2- it undergoes-oxidationredox reactionreductiondisproportionation

Question

Toppr Admin · Accepted Answer

The decomposition reaction of H2O2 is as follows-2H2O2-x2192-2H2O-O2This is a disproportionation reaction as oxidation state of O changes from -x2212-1 to -x2212-2 and 0-xA0-Hence- during decomposition of H2O2- it undergoes disproportionation-

During decomposition of $H_{2} O_{2}$ , it undergoes:
oxidation
redox reaction
reduction
disproportionation

The decomposition reaction of $H_{2} O_{2}$ is as follows:
$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$

This is a disproportionation reaction as oxidation state of $O$ changes from $- 1$ to $- 2$ and $0$ .

Hence, during decomposition of $H_{2} O_{2}$ , it undergoes disproportionation.

During decomposition of H2O2, it undergoes:oxidationredox reactionreductiondisproportionation

The decomposition reaction of H2O2 is as follows:2H2O2→2H2O+O2This is a disproportionation reaction as oxidation state of O changes from −1 to −2 and 0. Hence, during decomposition of H2O2, it undergoes disproportionation.

During decomposition of $H_{2} O_{2}$ , it undergoes:
oxidation
redox reaction
reduction
disproportionation

The decomposition reaction of $H_{2} O_{2}$ is as follows:
$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$

This is a disproportionation reaction as oxidation state of $O$ changes from $- 1$ to $- 2$ and $0$ .

Hence, during decomposition of $H_{2} O_{2}$ , it undergoes disproportionation.