During the electrolysis of copper sulphate solution with copper electrodes, how many coulombs of electricity should pass to oxidise half gram atom of copper to ${C u}^{2 +}$ ions?

Question

During the electrolysis of copper sulphate solution with copper electrodes- how many coulombs of electricity should pass to oxidise half gram atom of copper to -Cu-2- ions-965004825019300095600

Toppr Admin · Accepted Answer

1 gram atom of copper will require 2 faraday of electricity to convert into Cu-2 ions-Cu-x21CC-Cu-II-2eHalf gram atom of copper will require 1 faraday of electricity to convert to Cu2- ions-1 faraday - 96500 coulomb charge

During the electrolysis of copper sulphate solution with copper electrodes, how many coulombs of electricity should pass to oxidise half gram atom of copper to ${C u}^{2 +}$ ions?
$96500$
$48250$
$193000$
$95600$

1 gram atom of copper will require 2 faraday of electricity to convert into $C u^{+} 2$ ions.
$C u ⇌ C u (I I) + 2 e$
Half gram atom of copper will require 1 faraday of electricity to convert to $C u^{2 +}$ ions.
1 faraday = 96500 coulomb charge

During the electrolysis of copper sulphate solution with copper electrodes, how many coulombs of electricity should pass to oxidise half gram atom of copper to Cu2+ ions?965004825019300095600

1 gram atom of copper will require 2 faraday of electricity to convert into Cu+2 ions.Cu⇌Cu(II)+2eHalf gram atom of copper will require 1 faraday of electricity to convert to Cu2+ ions.1 faraday = 96500 coulomb charge

During the electrolysis of copper sulphate solution with copper electrodes, how many coulombs of electricity should pass to oxidise half gram atom of copper to ${C u}^{2 +}$ ions?
$96500$
$48250$
$193000$
$95600$

1 gram atom of copper will require 2 faraday of electricity to convert into $C u^{+} 2$ ions.
$C u ⇌ C u (I I) + 2 e$
Half gram atom of copper will require 1 faraday of electricity to convert to $C u^{2 +}$ ions.
1 faraday = 96500 coulomb charge