Each face of a cube has perimeter equal to 32 cm- Find its surface area

Question

Toppr Admin · Accepted Answer

The faces of a cube are squares-xA0-Let-xA0-the side of the square or the cube -a cmPerimeter of the square -4a-32 cm -x2192-a-8 cm-xA0-Total surface area of a cube of edge a-xA0-6a2-xA0-So- the total surface area of the cube of edge a-xA0-8 cm is 6-8-2-384cm2

Each face of a cube has perimeter equal to $32$ cm. Find its surface area

The faces of a cube are squares.
Let the side of the square or the cube $= a$ cm
Perimeter of the square $= 4 a = 32$ cm $\to a = 8$ cm
Total surface area of a cube of edge $a$ $= 6 a^{2}$
So, the total surface area of the cube of edge $a$ $= 8$ cm is $6 {(8)}^{2} = 384 {c m}^{2}$

Each face of a cube has perimeter equal to 32 cm. Find its surface area

The faces of a cube are squares. Let the side of the square or the cube =a cmPerimeter of the square =4a=32 cm →a=8 cm Total surface area of a cube of edge a =6a2 So, the total surface area of the cube of edge a =8 cm is 6(8)2=384cm2

Each face of a cube has perimeter equal to $32$ cm. Find its surface area

The faces of a cube are squares.
Let the side of the square or the cube $= a$ cm
Perimeter of the square $= 4 a = 32$ cm $\to a = 8$ cm
Total surface area of a cube of edge $a$ $= 6 a^{2}$
So, the total surface area of the cube of edge $a$ $= 8$ cm is $6 {(8)}^{2} = 384 {c m}^{2}$