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each other at right angles at point o. A person walking at a straight tracks AOB and COD meet each other at right angles at AOB is at the crossing o at 12 o'clock noon. Another person walking at the COD reaches the crossing O at 1:30 PM. If the time at which the distance between speed of 5 km/h along AOB is at th same speed along COD reaches th them is least is 12:T PM, then find T.

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Similar Questions

Q1

Two long identical conducting wires

AOB

and

COD

are placed at right angles to each other. The wire

AOB

carries an electric current

I_{1}

and

COD

carries a current

I_{2}

. Find the magnetic field at point

P

at a distance

d

from the intersection point

O

, in a direction perpendicular to the plane of the wires

AOB

and

COD

is-

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Q2

If the diagonals of a quadrilateral are equal and bisect each other at right angles, then prove that it is a square.

In ∆AOB and ∆COD, we have

AO = OC [Given]

BO = OD [Given]

∠AOB = ∠COD [Vertically opposite angles]

So, ∆AOB ≅ ∆COD, by S.A.S axiom of congruency (1 mark)

By C.P.C.T, we have

AB = CD

and ∠OAB = ∠OCD

But these are alternate angles

AB || CD (1 mark)

Thus, ABCD is a parallelogram

In a parallelogram, the diagonal bisect each other and are equal

Hence, ABCD is a square. (1 mark)

View Solution

Q3

Two roads cross at right angles at

O

. One person

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walking along one of the roads at

3 m s^{- 1}

sees another person B walking at

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along the other road at

O

, when he is

10 m

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Q4

The diagonal of a rectangle ABCD intersect each other at O. If

∠ A O B = 30^{o}

, find

∠ C O D

and

∠ O C D

View Solution

Q5

In the given figure,

A O B

is a straight line. If

∠ A O C + ∠ C O D = 100^{o}

and

∠ B O D + ∠ C O D = 146^{o}

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