Einstein-s photoelectric equation ishv-frac -W-0-w-mv-2hv-W-0-frac -1-2-mv-2hv-frac -1-2-m-2-W-0hv-W-0-frac -1-2-mv-2

Question

Toppr Admin · Accepted Answer

K-E- of the photo-electrons - -Energy obtained from the Photon- -x2013- -energy used to escape the metallic surface-Rearranging the equation gives us option c as the correct answer-

Einstein's photoelectric equation is
$h v = \frac{W_{0}}{w} - m v^{2}$
$h v = W_{0} - \frac{1}{2} m v^{2}$
$h v = \frac{1}{2} m^{2} - W_{0}$
$h v = W_{0} + \frac{1}{2} m v^{2}$

K.E. of the photo-electrons = (Energy obtained from the Photon) – (energy used to escape the metallic surface)
Rearranging the equation gives us option c as the correct answer.

Einstein's photoelectric equation ishv=W0w−mv2hv=W0−12mv2hv=12m2−W0hv=W0+12mv2

K.E. of the photo-electrons = (Energy obtained from the Photon) – (energy used to escape the metallic surface)Rearranging the equation gives us option c as the correct answer.

Einstein's photoelectric equation is
$h v = \frac{W_{0}}{w} - m v^{2}$
$h v = W_{0} - \frac{1}{2} m v^{2}$
$h v = \frac{1}{2} m^{2} - W_{0}$
$h v = W_{0} + \frac{1}{2} m v^{2}$

K.E. of the photo-electrons = (Energy obtained from the Photon) – (energy used to escape the metallic surface)
Rearranging the equation gives us option c as the correct answer.