Electric charges q,q and −2q are placed at the corners of an equilateral triangle ABC of side L. The magnitude of electric dipole moment of the system is
qL
2qL
(√3)qL
4qL
A
qL
B
4qL
C
2qL
D
(√3)qL
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Solution
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Electric dipole is a vector quantity
∴ Components along X-axis of →P1 and →P2 cancel out each other(opposite direction).
∴ Components along Y-axis will add up as:
∣→Pret∣=[(q⋅L)cos30∘]×2
=q⋅L⋅√32×2=√3qL
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