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Question

Electric potential at any point due to a point charge is 300 volt and intensity of electric field is $$ 50 \mathrm{V} / \mathrm{m} $$. The distance of charge of that point is.

A
$$ 15 \mathrm{m} $$
B
$$ 9 \mathrm{m} $$
C
$$ 6 \mathrm{m} $$
D
$$ 3 \mathrm{m} $$
Solution
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Correct option is C. $$ 6 \mathrm{m} $$
(c) $$ 6 \mathrm{m} $$ Electric field intensity $$ E=\dfrac{V}{d} $$
$$ \therefore d=\dfrac{V}{E} \Rightarrow d=\dfrac{300}{50} \Rightarrow d=6 \mathrm{m} $$

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